氧化还原反应配平难度较大,普遍失分较多,现将常用的两种配平方法总结如下,供同学们参考:
一、半反应配平法
1、Balance Redox Equations Under Acidic Conditions
①Construct unbalanceed oxidation and reduction half -equations
②Balance all elements except H and O
③Balance O atoms by adding H2O
④Balance H atoms by adding H+
⑤Balance charges by adding electrons to either LHS or RHS of the half-equations
⑥Balance electron transfer by multiplying appropriate integers
⑦Add the resulting half-equations and eliminate any common terms
⑧Check that there is mass and charge balance,with no electrons left in equation
2、Balance Redox Equations Under Alkaline Conditions after step 7
①Neutralisse the H+ions by adding the required number of OH-ions to both sides of half-equation and combine H+ions and OH-ions to form water
②Re-balance the half-equation by eliminating any common terms
For example:
9701_w21_qp119
Balance the equation:Cr2O72-+Zn+H+→Cr3++Zn2++H2O
①Cr2O72-+Zn+H+→Cr3++Zn2++H2O
②Cr2O72-→2Cr3+
③Cr2O72-→2Cr3++7H2O
④14H++Cr2O72-→2Cr3++7H2O
⑤6e-+14H++Cr2O72-→2Cr3++7H2O Zn→Zn2++2e-
⑥3Zn→3Zn2++6e-
⑦=⑤+⑥ 3Zn+14H++Cr2O72-→3Zn2++2Cr3++7H2O
⑧Check the mass and charges of the overall equation.
二、氧化数配平法
①Find the elements whose valence has changed and mark the valence value
②Mark the directions and number of electrons transferred
③Find the least common multiple to determine the coefficients
④Check that there is mass and charge balance
For example:
9701_w21_qp119
Balance the equation:Cr2O72-+Zn+H+→Cr3++Zn2++H2O
①Reactant Cr→+6;Product Cr→+3;we know 1mol Cr2O72-gains 6mol e-
Reactant Zn→0;Product Zn→+2;we know 1mol Zn loses 2mol e-
②Omitting
③6×1=6;2×3=6; 3 is the coefficient of Zn;1 is the coefficient of Cr2O72-
1Cr2O72-+3Zn+H+→Cr3++Zn2++H2O
1Cr2O72-+3Zn+H+→2Cr3++3Zn2++H2O
Balance the Charge
1Cr2O72-+3Zn+14H+→2Cr3++3Zn2++H2O
Balance the water
1Cr2O72-+3Zn+14H+→2Cr3++3Zn2++7H2O
以上为两种常见且效率很高的氧化还原配平方法,第一种适用于元素化合价不好确定的情形或是离子反应中,第二种方法较为常规,望同学们多加练习,熟能生巧。